One mole of an ideal monatomic gas undergoes the process `P=alphaT^(1//2)`, where `alpha` is constant . If molar heat capacity of the gas is `betaR1` when `R` = gas constant then find the value of `beta`.

Answer

2

Explanation

`PalphaT^(1//2)` and `PV = nRt implies PV^(-1)` = constant `therefore C=C_(v) + (R)/(1-(-1)) = (3R)/(2) + (R)/(2) = 2R`