A faulty thermometer reads freezing point and boiling point of water as `-5 ^(@)C` abd `95^(@)C` respectively . What is the correct value of temperature as it reads `60^(@)C` on faulty thermometer?

Options

A. `60^(@)C`
B. `65^(@)C`
C. `64^(@)C`
D. `62^(@)C`

Explanation

To solve the problem of determining the correct temperature reading when the faulty thermometer reads 60°C, we can use the concept of linear interpolation based on the known freezing and boiling points.

### Step-by-Step Solution:

1. **Identify the Fixed Points:**
- The faulty thermometer reads the freezing point of water as \(-5°C\) and the boiling point as \(95°C\).
- The actual freezing point of water is \(0°C\) and the boiling point is \(100°C\).

2. **Set Up the Proportionality:**
- We can set up a proportion based on the readings of the faulty thermometer and the actual temperature scale.
- Let \(C\) be the correct temperature corresponding to the faulty thermometer reading of \(60°C\).

3. **Establish the Equation:**
- The relationship can be expressed as:
\[ \frac{60 - (-5)}{95 - (-5)} = \frac{C - 0}{100 - 0} \]
- Simplifying the left side:
\[ \frac{60 + 5}{95 + 5} = \frac{C}{100} \]
\[ \frac{65}{100} = \frac{C}{100} \]

4. **Cross-Multiply to Solve for C:**
- Cross-multiplying gives:
\[ 65 \cdot 100 = C \cdot 100 \]
- Thus, we find:
\[ C = 65°C \]

5. **Conclusion:**
- Therefore, the correct value of temperature when the faulty thermometer reads \(60°C\) is \(65°C\).

### Final Answer:
The correct temperature reading is \(65°C\).