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A steel scale is to be prepared such tha...

A steel scale is to be prepared such that the millimeter intervals are to be accurate within `6 xx10^(-5)mm`. The maximum temperature variation form the temperature of calibration during the reading of the millimeter marks is `(alpha = 12 xx 10^(-6)//"^(@)C)`

A

`4.0^(@)C`

B

`4.5^(@)C`

C

`5.0^(@)C`

D

`5.5^(@)C`.

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaL= 6xx10^(-5) = Lalphatheta implies theta = (6xx10^(-5))/(1 xx 12 xx 10^(-6) =5^(@)C`
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