The expansion of unit mass of a perfect gas at constant pressure is shown in the diagram . Here :-

Options

A. a= volume, b = `"^(@)C` temperature
B. a= volume, b = `K`temperature
C. a= `"^(@)C` temperature , b = volume
D. a = `K` temperature , b= volume

Answer

C

Explanation

From Stefan's law of cooling :
`esigmaA(T^(4)-T_(0)^(4)) = ms((-dT)/(dt))`
`implies 1 xx 5.8 xx 10^(-8) xx pi xx (0.08)^(2) xx (500^(4) - 300^(4))`
= ` 10 xx90 xx 4.2 xx ((-dT)/(dt)) implies ((-dT)/(dt)) = 0.067 ^(@)C//s`