A gas is expanded from volume `V_(0) = 2V_(0)` under three different processes. Process `1` is isobaric process, process `2` is isothermal and process `3` is adiabatic. Let `DeltaU_(1), DeltaU_(2) and DeltaU_(3)` be the change in internal energy of the gas in these three processes. then

Options

A. `DeltaU_(1) gt DeltaU_(2) gt DeltaU_(3)`
B. `DeltaU_(1) lt DeltaU_(2) lt DeltaU_(3)`
C. `DeltaU_(2) lt DeltaU_(1) lt DeltaU_(3)`
D. `DeltaU_(2) lt DeltaU_(3) lt DeltaU_(1)`

Answer

A

Explanation

`DeltaU_(1) = +ve`
`DeltaU_(2) = 0`
`DeltaU_(3) = -ve`
`therefore DeltaU_(1) gt DeltaU_(2) gt DeltaU_(3)`
As volume increases , `DeltaW = +ve`.