N molecules, each of mass m of gas `A and 2 N` molecules each of mass `2m` of gas `B` are containted in the same vessel which is maintained at temperature T. The mean square velocity of molecules of B type is denoted by `v^(2)` and the mean square velocity of A type is denoted by `(omega)^(2)`. the `omega^(2)//v^(2)` is:

Options

A. `1`
B. `2`
C. `1//3`
D. `2//3`

Answer

D

Explanation

`V_(A)= sqrt((3RT)/(m)) = (w)/(sqrt(3)) , V_(B) = sqrt((3RT)/(2m)) = v implies (w^(2))/(v^(2)) = (2)/(3)`