Suppose `0.5` moles of an ideal gas undergoes an isothermal expansion as energy is added to it as heat Q. graph shows the final volume `V_(f)` versus Q. the temperature of the gas is `(use In 9 = 2 and R = (25)/(3) J//mol-K)`

Options

A. `293K`
B. `360K`
C. `386K`
D. `412K`

Answer

B

Explanation

` Q = W = nRT ln"(V_(f))/(V_(t))`
`T = (Q)/(nRlnV_(f)//V_(t)) = (1500)/(0.5 xx 25//3 xx ln3)`
=`(1500)/(0.5 xx 25//3 xx1) = 360K`