For one mole of a monoatomic gas :-
`{:(,"Column-I",,"Column-II"),((A),"Isothermal bulk modulus, ",(p),-(RT)/(V^(2))),((B),"Adiabatic bulk modulus ",(q),-(5P)/(3V)),((C),"Slope of P-V graph in isothermal process " ,(r),"T/V"), ((D), "Slope of P-V graph in adiabatic process",(s),"4T/3V"),(,,(t),"None"):}`

Explanation

To solve the problem, we need to match the items in Column I with the correct expressions in Column II for a monoatomic gas. Let's analyze each item step by step.

### Step 1: Isothermal Bulk Modulus (A)
The isothermal bulk modulus \( B \) is defined as:
\[ B = -\frac{dp}{dV} \]
For an isothermal process, we know that \( PV = nRT \). For one mole of gas, \( P = \frac{RT}{V} \).
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