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Five moles of helium are mixed with two ...

Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium `M_(1) = 4g` and that of hydrogen `M_(2) = 2g`
The equivalent molar mass of the mixture is

A

`6g`

B

`(13)/(7)g`

C

`(18)/(7)g`

D

None

Text Solution

Verified by Experts

The correct Answer is:
D
`M_(mtx) = (n_(1)M_(1) + n_(2)M_(2))/(n_(1) + n_(2)) = (5 xx 4 + 2 xx 2 )/(7) = (24)/(7)g`
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