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Five moles of helium are mixed with two ...

Five moles of helium are mixed with two moles of hydrogen to form a mixture. Take molar mass of helium `M_(1) = 4g` and that of hydrogen `M_(2) = 2g`
The equivalent degree of freedom f of the mixture is

A

`3.57`

B

`1.14`

C

`4.4`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`C_(V"mtx") = ((5)/(2) xx 2R + (3)/(2)xx 5R)/(7) = (f_("mtx"))/(2)R = f_("mtx") = 3.57`
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