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The figure shows the face and interface temperature of a composite slab containing of four layers of two materials having identical thickness. Under steady state condition, find the value of temperature `theta`.

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The correct Answer is:
`5^(@)C`
`(DeltaQ)/(Deltat) = "same So" (KA(20-10))/(l) = (2KA(10-0))/(l) implies 2 theta = 10 implies theta = 5 ^(@)C`
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