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Two glass bulbs of equal volume are connected by a narrow tube and are filled with a gas at `0^@C` and a pressure of 76cm of mercury. One of the bulbs is then placed in melting ice and the other is placed in a water bath maintained at `62^@C`. What is the new value of the pressure inside the bulbs? The volume of the connecting tube is negligible.

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Verified by Experts

The correct Answer is:
`83.83` cm of Hg
No. of moles (initially) = No. of moles (finally) `(76 xx V_(0))/(273) + (76 xx V_(0))/(273) = (PV_(0))/(273) + (PV_(0))/(335)`
`implies P = 83.83` cm of Hg
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ALLEN-GEOMETRICAL OPTICS-EXERCISE - 04 (A)
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