One mole of an ideal gas is heated isobarically from the freezing point to the boiling point of water each under normal pressure . Find out the work done by the gas and the change in its internal energy. The amount of heat involved is `1`kJ.

Answer

`830J , 170J`

Explanation

`DeltaU = nC_(V)DeltaT , Q = nC_(P)DeltaT "and" W = nRDeltaT = (1)((25)/(3)) (100) = (2500)/(3) J`
`DeltaU = n(C_(P) -R)DeltaT = nC_(P)DeltaT - nRDeltaT`
=`1000-(1) ((25)/(3)) (100)= (500)/(3)J`