A gaseous mixture consists of 16g of helium and 16 g of oxygen. The ratio `(C_p)/(C_v)` of the mixture is

Options

A. `1.59`
B. `1.62`
C. `1.4`
D. `1.54`

Answer

A

Explanation

`(n_(1) + n_(2))/(gamma_("mix") - 1) = (n_(1))/(gamma_(1) -1) + (n_(2))/(gamma_(2) -1)`
Number of moles in `16` hg He =`4`
Number of moles in `16` g `O_(2) = 0.5`
`gamma_(He) = (5)/(3) gamma_(O_(2)) = (7)/(5)`
On replacing `n_(He) n_(O_(2)), gamma_(He) , gamma_(O_(2))`
`gamma_("mtx") = 1.62`