If `C_(p) and C_(v)` denoted the specific heats of unit mass of nitrogen at constant pressure and volume respectively, then

Options

A. `C_(P) - C_(V) = R//28`
B. `C_(P) - C_(V) = R//14`
C. `C_(P) - C_(V) = R`
D. `C_(P) - C_(V) = 28 R`

Answer

A

Explanation

We have , molar heat capacity = molar mass `xx` specific heat capacity per unit mass
`therefore C_(P) = 28 C_(P) ("for nitrogen ") "and" C_(V) = 28C_(V)`
Now `C_(P) - C_(V) = R "or" 28 C_(P) - 28 C_(V) = R`
`implies C_(P) - C_(V) = (R)/(28)`