An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature as

Options

A.
B.
C.
D.

Answer

C

Explanation

As `P` = constant so `PDeltaV = nRDeltaT implies delta = (DeltaV)/(VDeltaT) = (nR)/(PV) = (1)/(T)`