An insulated box containing a monoatomic gas of molar mass (M) moving with a speed `v_0` is suddenly stopped. Find the increment is gas temperature as a result of stopping the box.

Answer

`(Mv_(0)^(2))/(3R)`

Explanation

Decrease in kinetic energy = increase in internal energy of the gas
`therefore (1)/(2)mv_(0)^(2) = nC_(V)DeltaT = ((m)/(M))((3)/(2)R)DeltaT therefore DeltaT = (Mv_(0)^(2))/(3R)`