A metal rod AB of length 10x has its one end A in ice at `0^@C`, and the other end B in water at `100^@C`. If a point P one the rod is maintained at `400^@C`, then it is found that equal amounts of water and ice evaporate and melt per unit time. The latent heat of evaporation of water is `540cal//g` and latent heat of melting of ice is `80cal//g`. If the point P is at a distance of `lambdax` from the ice end A, find the value `lambda`. [Neglect any heat loss to the surrounding.]

Answer

9

Explanation

`(k(400-0)A)/(L) = m(80) …. (i)`
`(kA(400-100))/((10x-L)) = m(540) …..(ii)`
Divide (i) by (ii) `1080 x = 120L`
`because L = lambdax therefore = lambda = 9`