A ray of light passes through an equilateral prism (refractive index `1.5`) such that angle of incidence is equal to angle of emergence and the latter is equal to `3//4 th` of the angle of prism. Calculate the angle of deviation.

Explanation

`A = 60^(@), mu = 1.5 , i_(1) = i_(2) = (3)/(4)A = 45^(@), delta= ?`
`because A + delta = i_(1) + i_(2) " " therefore 60^(@) + delta = 45^(@) + 45^(@) implies delta = 90^(@) - 60^(@) = 30^(@)`