Home
Class 12
PHYSICS
In a displacement method the distance be...

In a displacement method the distance between the object and the screen is `70` cm and the focal length of the lens is `16` cm, find the separations of the magnified and diminished image position of the lens.

Text Solution

Verified by Experts

`d = sqrt(D^(2) - 4fd) = sqrt((70)^(2) - 4 xx 16 xx 70) = sqrt(420) = 20.5 "cm"`
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    ALLEN|Exercise SOME WORKED OUT EXAMPLES|84 Videos

  • GEOMETRICAL OPTICS

    ALLEN|Exercise EXERCISE -01|65 Videos

  • CURRENT ELECTRICITY

    ALLEN|Exercise All Questions|427 Videos

  • GRAVITATION

    ALLEN|Exercise EXERCISE 4|9 Videos

Similar Questions

Explore conceptually related problems

In the displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the seperation of the magnified and diminished image position of the lens.

In displacement method, the distance between object and screen is 96 cm. The ratio of length of two images formed by a convex lens placed between them is 4.84.

An object and the image obtained from the lens are as given above. If the distance between the object and the image is 36 cm and the magnification is -2, find the focal length of the lens and draw the ray diagram to show the position of the lens.

In displacement method, the distance between object and screen is 96cm. The ratio of lengths of two images formed by a converging lens placed between them is 4. Then,

Find the distance of an object from a convex lens if image is two times magnified. Focal length of the lens is 10cm

The distance between the object and the screen is d (greater than 4 times the focal length of a convex lens). Real images of the object are obtained on the screen for two positions of the lens that are separated by distance x apart. The ratio of size of the images in the two positions of the lens are

A convex lens when placed in the first position forms a real image of an object on a fixed screen. The distance between the object and the screen is 75 cm. On displacing the lens from first position by 25 cm to the second position, again a real image is formed on the screen. Then the focal length of the lens is

When the distance between the object and the screen is more than 4 f . We can obtain image of the object on the screen for the two positions of the lens. If is called displacement method. In one case, the image is magnified and in the other case, it is diminished. If I_(1) and I_(2) be the sized of the two images, then the size of the object is