Optic axis of a thin equiconvex lens is the x-axis. The co-rodinates of a point object and its image axis `(-40 cm, 1 cm)` and `(50 cm, -2 cm)` respectively. Lens is located at

Answer

C

Explanation

`m = (-2)/(1) = -2 = (v)/(u) implies |v| = |2u|`
`(90-u) = 2u implies u = 30 "cm"`

Hence lens location = -40 + 30 =-10 cm