A beaker contains water up to a height `h_(1)` and kerosene of height `h_(2)` above water so that the total height of (water + kerosene) is `(h_(1) + h_(2))` . Refractive index of water is `mu_(1)` and that of kerosene is `mu_(2)` . The apparent shift in the position of the bottom of the beaker when viewed from above is :-

Options

A. `(1 - (1)/(mu_(1)))h_(2)`
B. `(1 - (1)/(mu_(1)))h_(1) +(1 -(1)/(mu_(2)))h_(2)`
C. `(1 - (1)/(mu_(1)))h_(1)`
D. `(1 + (1)/(mu_(1)))h_(2) - (1 + (1)/(mu_(2)))h_(1)`

Answer

C

Explanation

Apparent shift = `h(1-(1)/(mu))`

Total apparent shift = `h_(1) (1- (1)/(mu)) + h_(2) (1 - (1)/(mu_(2)))`