A mass M is performing linear simple harmonic motion. Then correct graph for acceleration a and corresponding linear velocity v is

Options

A.
B.
C.
D.

Answer

B

Explanation

`v = A omegacos omegat, a = -omega^(2)A sin omegat`
`rArr ((v)/(Aomega))^(2) +((a)/(omega^(2) A))^(2) = 1`
`rArr` Straight line in `v^(2)` and `a^(2)`