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A mass of 0.2 hg is attached to the lowe...

A mass of 0.2 hg is attached to the lower end of a massles spring of force constant `200(N)/(m)` the opper end of which is fixed to a rigid support. Study the following statements.

A

in equilibrium, the spring will be stretched by `1 cm`.

B

If the mass is raised till the spring is unstretched state and then relesed, it will go down by `2cm` before moving upwards.

C

The freuqunecy of oscillation will be nearly `5 Hz`.

D

If the system is taken to the moon, the frequency of oscillation wil be the same as on the earth.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

At equilibrium mg `= kx_(0)`
`rArr x_(0) = (mg)/(k) = ((0.2)(10))/(200) = 0.01 m = 1 cm`
Amplitude of SHM
Frequency `= 1/2pi sqrt((k)/(m)) = 1/2pi sqrt((200)/(0.2)) approx 5 Hz`.
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