Home
Class 12
PHYSICS
The surface of a metal of work funcation...

The surface of a metal of work funcation `phit` is illumicated by light whose electric field component varies with time as `E = E_(0) [1 + cos omegat] sinomega_(0)t`. Find the maximum kinetic energy of photonelectrons emitted from the surface.

Text Solution

Verified by Experts

The given electric field component is `e = E_(0)sin omega_(0) t + E_(0) sinomegat cos omegat`
`= E_(0)sin omega_(0)t + (E_(0))/(2)[sin (omega_(0) + omega) t + sin(omega_(0) - omega)t]`
`:.` The given light comprises three different frequencies viz. `omega, omega_(0) + omega, omega_(0)-omega`
the maximum kinetic energy will be due to most energetic photon. `:. KE_(max) = hv - phi = (h(omega + omega_(0)))/(2pi) - phi (:' omega = 2piv` or `v = (omega)/(2pi)`
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Photo Elertric Effectric : Solved Example|1 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Matter Waves Theory : Solved Example|4 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise X Rays : Solved Example|2 Videos
  • RACE

    ALLEN|Exercise Basic Maths (Wave Motion & Dopplers Effect) (Stationary waves & doppler effect, beats)|25 Videos
  • TEST PAPER

    ALLEN|Exercise PHYSICS|4 Videos

Similar Questions

Explore conceptually related problems

If light of wavelength of maximum intensity emitted from surface at temperature T_(1) Is used to cause photoelectric emission from a metallic surface, the maximum kinetic energy of the amitted electron is 6 ev, which is 3 time the work function of the metallic surface. If light of wavelength of maximum intensity emitted from a surface at temperature T_(2) (T_(2)=2T_(1)) is used, the maximum kinetic energy of the photoelectrons emitted is

Statement-1 : Light described at a place by the equation E= E_(0) (sin omegat + sin 7 omegat) falls on a metal surface having work funcation phi_(0) . The macimum kinetic energy of the photoelectrons is KE_(max) = (7homega)/(2pi) - phi_(0) Statement-2 : Maximum kinetic energy of photoelectron depends on the maximum frequency present in the incident light according to Einstein's photoelectric effect equation.

Light of wavelength 2000Å is incident on a metal surface of work function 3.0 eV. Find the minimum and maximum kinetic energy of the photoelectrons.

A particle of mass m and charfe Q is placed in an electric filed W which varies with time t as E = E_(0) sin omegat . It will undergo simple harmonic motion of amplitude.

Find the maximum kinetic enegry of photoelectrons liberated form the surface of lithium by electromagnetic radiation whose electric component varies with time as E = a(1+cos omegat) cos omega_(0)t , where a is a constant, omega = 6.0.10^(14)s^(-1) and omega_(0) = 360.10^(15)s^(-1) .

Light of wavelength 4000 Å is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface ?

The stopping potential for photoelectrons emitted from a surface illuminated by light wavelength of 5893A is 036 V . Calculate the maximum kinetic energy of photoelectrons, the work function of the surface, and the threshold frequency.

The photoelectros emitted by an illuminted surface have a maximum kinetic energy of 3.0 eV. If the intensity of the light is tripled, What is the maximum kinetic energy of photoelectrons now?

When monochromatic light of wavelength 620 nm is used to illuminate a metallic surface, the maximum kinetic energy of photoelectrons emitted is 1 eV. Find the maximum kinetic energy of photoelectron emitted (in eV) if a wavelength of 155 nm is used on the same metallic surface. (hc = 1240 eV-nm)