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If the kinetic energy of a free electron...

If the kinetic energy of a free electron doubles , its de - Broglie wavelength changes by the factor

A

`1/2`

B

`2`

C

`1/(sqrt(2))`

D

`sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
The de-Brogile wavelengths and kinetic energy of a free electron are related as
`lambda=h/sqrt(2mK)implies lambda_(2)/lambda_(1)=sqrt(K_(1)/K_(2))=sqrt(1/2)implies lambda_(2)=lambda_(1)/sqrt(2)`
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