If the source of power` 4 kW` product`10^(20)` photons //second , the radiation belongs to a part spectrum called

Options

A. `gamma-`rays
B. `X-`rays
C. ultraviolet rays
D. microwaves

Answer

B

Explanation

No. of photons emitting per second from a source of power P is `n=(5xx10^(24))Plambda`
`implies` wavelength emitting `lambda=(n)/((5xx10^(24))P)["or "lambda=(nhc)/P]`
`implies lambda= 10^(20)/(5xx10^(24)xx4xx10^(3))=0.5xx10^(-9)m=50 Å`
and this wavelength comes in X ray region