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The binding energies per nucleon for deu...

The binding energies per nucleon for deuteron (`._1H^2`) and helium (`._2He^4)` are `1.1 MeV` and `7.0 MeV` respectively. The energy released when two deutrons fuse to form a helium nucleus (`._2He^4`) is……..

A

`13.9 MeV`

B

`26.9 MeV`

C

`23.6 MeV`

D

`19.2 MeV`

Text Solution

Verified by Experts

The correct Answer is:
C
Given that `.^(2)H_(1) + .^(2)H_(1) rarr .^(4)He_(2) +` energy total B.E. of deuterium nucleus `= 28 MeV` On conservating energy on both sides we get `("Energy")_("Deutron") xx 2 = ("Energy")_(He) +` Energy released
`rArr 4.4 = 28 + E`
`rArr E = 28 - 4.4 = 23.6 MeV`
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