A nuclear transformation is denoted by `X(n,alpha) rarr. _(3)^(7)Li`. Which of the following is the nucleus of element `X`

Options

A. `._(6)^(12)C`
B. `._(5)^(10)B`
C. `._(5)^(9)B`
D. `._(4)^(11)Be`

Answer

B

Explanation

`X (n, alpha) rarr ._(3)^(7)Li`
`._(0)^(1)n + ._(Z)^(A)X rarr ._(3)^(7)Li + ._(2)^(4)He`
On conservating atomic number and mass number on both sides, we get
`A = (7 + 4) - 1 = 10`
`Z = (3 + 2) - 0 = 5`
Hence, `._(Z)^(A)X = ._(5)^(10)B`