If the binding energy per nucleon in `._(3)Li^(7)` and `._(2)He^(4)` nuclei are respectively `5.60` MeV and `7.06` MeV, then the ebergy of proton in the reaction `._(3)Li^(7) +p rarr 2 ._(2)He^(4)` is

Options

A. `28.24 MeV`
B. `17.28 MeV`
C. `1.46 MeV`
D. `1.46 MeV`

Answer

B

Explanation

In a nuclear reaction the energy remains conservest
`P + ._(3)^(7)Li rarr 2(._(2)^(4)He)`
energy of proton `+ 7(5.60) = 2(4 xx 7.06)`
`rArr` energy of `= 17.28 MeV`