If `M_(o)` is the mass of an oxygen isotope `._(8)O^(17), M_(p)` and `M_(N)` are the masses of a proton and neutron respectively, the nuclear binding energy of the isotope is:

Options

A. `(M_(o) -8M_(p))C^(2)`
B. `(8Mp + 9M_(n) - M_(0))c^(2)`
C. `M_(o)c^(2)`
D. `(M_(o) - 17M_(n))c^(2)`

Answer

B

Explanation

Nuclear binding energy = [Expected mass of nucleus-Actual mass of nucleus]`c^(2)`
Expected mass of nucleus `= 8M_(P) + 9M_(n)`
Actual mass of nucleus `= M_(a)`
Nuclear binding energy `= [8M_(p) + 9M_(n) - M_(a)]c^(2)`