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Assume that a neutron breaks into a prot...

Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron `= 1.6725 xx 10^(-27) kg` mass of proton `= 1.6725 xx 10^(-27) kg` mass of electron `= 9 xx 10^(-31) kg )`

A

`5.4 MeV`

B

`0.73 MeV`

C

`7.10 MeV`

D

`6.30 MeV`

Text Solution

Verified by Experts

The correct Answer is:
B

Released energy
`=(1.6747xx10^(-27)-1.6725xx10^(-27)-9xx10^(-31))xx (3xx10^(8))^(2)J=0.73 MeV`
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Assume that a neutron breaks into a proton and an electron. The energy released during this process is (mass of neutron = 1.6725 xx 10^(-27) kg, mass of proton = 1.6725 xx 10^(-27) kg , mass of electron = 9 xx 10^(-31) kg)

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A neutron break into proton and electron. Calculate the energy produced in this reactions in MeV. ( m_e=9.1xx10^(-31)kg, m_p=1.6725xx10^(-27) kg , m_n=1.6747xx10^(-27) kg ) :-

The mass of 1 mole of neutrons (m_(n) = 1.675 xx 10^(-27) kg) is:

A neutron breaks into a proton and electorn. Calculate the eenrgy produced in this reaction in m_(e) = 9 xx 10^(-31) kg, m_(p) = 1.6725 xx 10^(-27) kg, m_(n) = 1.6747 xx 10^(-27) kg, c = 3xx10^(8)m//sec .

The kinetic energy of an electron is 4.55 xx 10^(-25)J . Calculate the wavelength . [h = 6.6 xx 10^(-34)Js , mass of electron = 9.1 xx 10^(-31)kg]

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ALLEN-SIMPLE HARMONIC MOTION-Exercise-04 [B]
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