The potential difference applied to an X-ray tube is 5k V and the current through it is 3.2 mA. Then, the number of electrons striking the target per second is. (a) `2xx10^16` (b) `5xx10^6` (c ) `1xx10^17` (d) `4xx10^15`.

Options

A. `2 xx 10^(14)`
B. `5 xx 10^(6)`
C. `1 xx 10^(12)`
D. `4 xx 10^(15)`

Answer

A

Explanation

`i=q/t=(n e)/t implies n= (I t)/e`
Substituting `=3.2xx10^(-3) A`
`e=1.6xx10^(-19) C` and `t=1 s`
We get, `n=2xx10^(16)`