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A pulse of light of duration 100 ps is a...

A pulse of light of duration `100 ps` is absorbed completely by a small object initially at rest. Power of the pulse is `30 W` and the speed of light is `3xx10^8 ms^(-1)`. The final momentum of the object is :

A

`0.3 xx 10^(-17)kg ms^(-1)`

B

`1.0 xx 10^(-17) kgms^(-1)`

C

`3.0 xx 10^(-17) kg ms^(-1)`

D

`9.0 xx 10^(-17) kg ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

`{:("Energy incident",=" Power (time)"),(,=(30 mw) (100 ns)),(,=3xx10^(-9)):}`
So momentum `=E/c=(3xx10^(-9))/(3xx10^(8))=10^(-17) kg m//sec`.
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