Home
Class 11
PHYSICS
Calculate the force acting between two s...

Calculate the force acting between two small magnets, placed in end on position `0.1 m` apart from their centres. (Given, magnetic moment of each magnet is `5 Am^(2)`).

A

0.6 N

B

0.8 N

C

0.15 N

D

0.2 N

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • MAGNETOSTATICS

    BITSAT GUIDE|Exercise BITSAT Archives|8 Videos

  • LAWS OF THERMODYNAMICS

    BITSAT GUIDE|Exercise 40|1 Videos

  • MOTION IN !,2,2 DIMENSIONS AND POJECTILE MOTION

    BITSAT GUIDE|Exercise All Questions|86 Videos

Similar Questions

Explore conceptually related problems

The small magnets each of magnetic moment 10 A-m^(2) are placed end-on position 0.1 m apart from their centres. The force acting between them is

A bar magnet of magnetic moment M is cut into two parts of equal length/breadths.The magnetic moment of each part will be

A short bar magnet is placed along positive X-axis with its centre at origin. Calculate the magnitude of magnetic field strength at point (0,5 cm), if the magnetic moment of the bar magnet is 0.5 Am^2

A magnet of magnetic moment M and pole strength m is divided in two equal parts, then magnetic moment of each part will be

A bar magnet of magnetic moment 20 Am^(2) is divided into two equal parts by cuting it along its axis. The magnetic moment of each part will be

The torque acting on a magnet of magnetic moment 'M' placed in a uniform magnetic field B is

Two magnets of magnetic moments 4Am^(2) and 3Am^(2) are joined to form a cross (+) , then the magnetic moment of the combination is

Calculate the work done in deflecting a small magnet of magnetic moment 10Am^(2) through 180^(@) from a uniform magnetic field of strength 0.4 xx 10^(-4)T .

The ratio of the magnetic fields due to small bar magnet in end position and on broad side position is (at equal distance from the magnet)