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A current I flows in a conducting wire o...

A current I flows in a conducting wire of lenth L. If we bent it in a circular form, then calculate its magnetic dipole moment.

A

`(ll)/(4pi)`

B

`(l^(2)l)/(4pi)`

C

`(ll^(2))/(4pi)`

D

`(l^(2)l^(2))/(4pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
Length of a conducting wire, `2pir=l, r=(l)/(2pi)`,
Area of coil, `alpha=pir^(2)=(pi.l^(2))/(4pi^(2))=(l^(2))/(4pi)`
`So, " " m=lA=(ll^(2))/(4pi)`
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