Home
Class 11
PHYSICS
The magnetic induction inside a solenoid...

The magnetic induction inside a solenoid is `6.5xx10^(-4)T`. When it is filled with iron medium, then the induction becomes `1.4 T`. The relative permeability of iron will be

A

1578

B

2355

C

1836

D

2154

Text Solution

Verified by Experts

The correct Answer is:
D
`B_("air")=mu_(0)nl, B_("medium")=mu_(0)u_(r )nl=mu_(r )B_(0)`
`1.4 = mu_(r )xx 6.5 xx 10^(-4)`
`therefore" "mu_(r )=(1.4)/(6.5 xx 10^(-4))=2154`
Promotional Banner

Topper's Solved these Questions

  • MAGNETOSTATICS

    BITSAT GUIDE|Exercise BITSAT Archives|8 Videos

  • LAWS OF THERMODYNAMICS

    BITSAT GUIDE|Exercise 40|1 Videos

  • MOTION IN !,2,2 DIMENSIONS AND POJECTILE MOTION

    BITSAT GUIDE|Exercise All Questions|86 Videos

Similar Questions

Explore conceptually related problems

An iron-cored solenoid has self- inductance. 2.8 H. When the core is removed, the self inductance becomes 2 mH. What is the relative permeability of the core used?

A magnetising field of 2xx10^(3)Am^(-1) produces a magnetic flux density of 8piT in an iron rod. The relative permeability of the rod will be

The magnetic induction and the intensity of magnetic field inside an iron core of an electromagnet are 1 Wbm^(-2) and 150Am^(-1) respectively. The relative permeability of iron is : (mu_(0)=4pixx10^(-7)"henry"//m)

A magnetic field strength (H) 3xx10^(3) Am^(-1) produces a magnetic field of induction (B) of 12piT in an iron rod. Find the relative permeability of iron ?

If self induction of an air core solenoid increases from 0.04 mH to 16 mH on introducing an iron core into it, what is relative magnetic permeability of the core ?

A solenoid having 100 turns with an area of cross section 10 cm^(2) is 12 cm long. When iron core is introduced in it, the self-inductance increases to 1000 times. Calculate the relative permeability of the core.