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A magnet is cut in three equal parts by ...

A magnet is cut in three equal parts by cutting it perpendicular to its length. The time period of original magnet is `T_0` in a uniform magnetic field B. Then, the time period of each part in the same magnetic field is

A

`(T_(0))/(sqrt(2))`

B

`(T_(0))/(2)`

C

`(T_(0))/(4)`

D

`4T_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
For each part, `l_(1)=(l)/(4)`
and `" "M_(1)=(M)/(2)`
`therefore" "T=2pisqrt(((l)/(MB)))`
and `" "T_(1)=2pi sqrt(((l_(1))/(M_(1)N)))=2pisqrt(((lxx2)/(4MxxB)))`
`therefore" "T_(1)/(T)=(1)/(sqrt(2))`
`therefore" "T_(1)=(T)/(sqrt(2))=(T_(0))/(sqrt(2))`
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