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The current on the winding of a toroid i...

The current on the winding of a toroid is 2 A. It has 400 turns and mean circumferential length is 40 cm. With the help of search coil and charge measuring instrument the magnetic field is found to be 1 T. The susceptibility is

A

100

B

290

C

398

D

397

Text Solution

Verified by Experts

The correct Answer is:
D
As, `n=(400)/(2piR)=(400)/(40xx10^(-2))=1000`
`mu=ni=1000xx2=2000`
`implies" "mu_(0)mu_(r )=(1)/(2000)=5xx10^(-4)`
`implies " "mu_(r )=(5xx10^(-4))/(mu_(0))=(5xx10^(-4))/(4pixx10^(-7))=398`
`implies " "chi=mu_(r )-1=397`
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