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An iron rod is subjected to cycles of ma...

An iron rod is subjected to cycles of magnetisation at the rate of `50Hz`. Given the density of the rod is `8xx10^(3)kg//m^(3)` and specific heat is `0.11xx10^(-3)calxxkg^(@)C`. The rise in temperature per minute, if the area enclosed by the `B-H` loop corresponds to energy of `10^(-2)J` is (Assume there is no radiation losses)

A

`78^(@)C`

B

`88^(@)C`

C

`8.1^(@)C`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Energy loss per unit volume per cycle = area of hysteresis loop
Energy loss per second per unit volume `=10^(-2)xx50J`
Also, heat produced Q in one minute per volume
`Q=10^(-2)xx50xx60J=(30)/(4.2)" cal"`
Let `theta` = rise in temperature
`because 8xx10^(3)xx0.11xx10^(-3)xxtheta=(30)/(4.2)`
`theta=(30)/(4.2xx8xx0.11)=8.1.^(@)C`
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