Let `f(x) = 2x^2 –10x , oo < x <= -5` and `f(x)=x^2-5 , -5 < x < 3` and `f(x)=x^2+1 , 3 <= x < oo ` Number of negative integers in the range of the function `f(x)` is

Let f (x) = x^(2)+10x+20. Find the number of real solution of the equation f (f (f (f(x))))=0

Let f (x) = x^(2)+10x+20. Find the number of real solution of the equation f (f (f (f(x))))=0

Let f(x) = (x^2 - 4)/(x^2 + 4) , for |x| > 2 , then the function f: (-oo , -2] cup [2, oo) to (-1,1) is :

Let f(x) = x + 1/(2x + 1/(2x + 1/(2x + ....oo))) " then " sqrt((f(50) f^'(50))/(2)) =

Let f:[2, oo) rarr X be defined by f(x) = 4x-x^2 . Then, f is invertible if X =

Let f(x)=x^(2)-2x-1AA x in R , Let f,(-oo,a] to [b,oo) , where 'a' is the largest real number for which f(x) is bijective. The value of (a+b) is equal to

Let f(x) = cos x - (1 - (x^(2))/(2)) then f(x) is increasing in the interval a) (-oo, 1] b) [0, oo) c) (-oo, -1] d) (-oo, oo)

Let f(x)=x^2-2x-1 AA x in R Let f:(-oo, a]->[b, oo) , where a is the largest real number for which f(x) is bijective. If f : R->R , g(x) = f(x) + 3x-1 , then the least value of function y = g(|x|) is

Let f(x)=x^2-2x-1 AA xinR Let f:(-oo, a]->[b, oo) , where a is the largest real number for which f(x) is bijective. If f : R->R , g(x) = f(x) + 3x-1 , then the least value of function y = g(|x|) is