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CuSO(4)(aq)+4NH(3)toX, then X is...

`CuSO_(4)(aq)+4NH_(3)toX`, then X is

A

`[Cu(NH_(3))_(4)]^(2+)`

B

paramagnetic

C

coloured

D

of a magnetic moment of `1.73 BM`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
`CuSO_(4)(aq)+NH_(3)to-X`
`" "(Cu(NH_(3))_(4))SO_(4)`
`" "sap^(2)`
paramagnetic with one unpaired `e^(-)`
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