Calculate work for the expansion of a subsatnce from `3m^(3)` to `5m^(3)` against.
Constant pressure `=10^(5)Pa`

Explanation

To calculate the work done during the expansion of a substance from \(3 \, m^3\) to \(5 \, m^3\) against a constant pressure of \(10^5 \, Pa\), we can follow these steps:

### Step 1: Identify the given values
- Initial volume, \(V_1 = 3 \, m^3\)
- Final volume, \(V_2 = 5 \, m^3\)
- External pressure, \(P = 10^5 \, Pa\)

### Step 2: Calculate the change in volume
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