A certain mass of a gas is expanded from (1L, 10 atm) to (4L, 5 atm) against a constant external pressure of 1 atm . If initial temperature of gas is 300 K and the heat capacity of process is `50 J//^(@)C. Calculate `DeltaH`(in kJ) of the process .(Given 1 L atm = 100 J).
(Fill your answer by multiplying it with 100 )

Explanation

`DeltaU=Q+W" "(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`=50 xx(600-300)-1(4-1)xx100 " "or" "(10xx1)/(300)=(5xx4)/(T_(2))`
`15000 - 300 J " or " " T_(2)=5xx4 xx 30 = 600 K`
`=14700 J`
`= 14.7 J `
`DeltaH=DeltaU +(P_(2)V_(2)-P_(1) V_(1))`
`=14.7 +((20-10)xx100)/(1000) `
`14.7 +1= 15.7 kJ= 1570`