A liquid confined inside an adiabatic container is suddenly taken from state 1 to state 2 by a single stages
process as shown, then `DeltaH` is

Options

A. `DeltaH=(2gammaP_(0)V_(0))/(gamma-1)`
B. `DeltaH = -P_(0)V_(0)`
C. `DeltaH = -3P_(0)V_(0)`
D. `DeltaH = -(3gammaP_(0)V_(0))/(gamma-1)`

Answer

B

Explanation

`Q=0`
`DeltaU= Q + W=w`
`W=- P_(0)(4V_(0)-V_(0))= - 3P_(0)V_(0)`
`DeltaH = DeltaU +(P_(2)V_(2)-P_(1)V_(1))`
` =- 3P_(0)V_(0)+(4P_(0)V_(0)-2P_(0)V_(0))`
`=- 3P_(0)V_(0)+2P_(0)V_(0)`
` = - P_(0)V_(0)`