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Consider the reaction at 300 K H(2)...

Consider the reaction at 300 K
`H_(2)(g)+Cl_(2)(g) to 2HCl(g)" "DeltaH = - 185 kJ//mol`
Calculate `DeltaU` if 3 mole of `H_(2)` completely react with 3 mo,le f of `Cl_(2)` to from HCl.

A

0

B

`-185 kJ`

C

`555 kJ`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`Deltan_(g) = 0 rArr DeltaH= DeltaU = - 185 kJ//"Mole"`
For three moles = - `185 xx 3 = - 555 `
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