Calculate `log_(10){[C]_(eq)//[A]_(eq)}` where [C] and [A] are equilirium molar concetration of respective
species, when 2 2 mole each of A and B were allowed to come to equilibrium at 900 K.
`A + B overset(900 K) hArrC + D" ", " "DeltaG^(@) = 460.6 "Calorie"`
Take: `underset(R=2 Cal //K"mole")(ln X = 2.303 log X)`

Options

A. `5.56 xx 10^(-02)`
B. `5.57 xx 10^(-03)`
C. `1.1 xx 10^(-2)`
D. `1.1 xx 10^(-3)`

Answer

A

Explanation

`DeltaG^(@)= 2.303 RT log K_(C)`
`460.6 = - 2.303 xx 2 xx 900 log K_(C)`
`log K_(C) = -(1)/(9)`
`log .([C]_(eq)^(2))/([A]_(eq)^(2))=(1)/(9)" "log.([C]_(eq))/([A]_(eq)) = -(1)/(18) = 5.56 xx 10 ^(2) " "("at equilibrium "[C]_(eq) = [D]_(eq)[A]_(eq)=[B]_(eq))`