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A cyclindrical container of volume 44...

A cyclindrical container of volume `44.8 litres` is containing equal no.of moles (in integer no. ) of an ideal
monoatomic gas in two sections A and B separeted by an adiabatic frictionless piston as show in figure
The initinal temperature and pressure of gas in both section B becomes `(1//8)^(th)` of initial volume .

Given : `R = 2 cal //"mole -K", C_(v,m)` of monoatmic gas `=(3)/(2)R`,
At 1 atm & `0^(@)` ideal gas occupy `22.4 liter`.
Find temperature in container A will be

A

1638 K

B

6988 k

C

3274 K

D

51 K

Text Solution

Verified by Experts

The correct Answer is:
A

After heating P in both container is equal
`(P_(1)V_(1))/(T_(1))=(P_(1)V_(1))/(T_(2))`
`V_(2)` of container `A = 22.4 +22.4 xx(7)/(8)`
`= 42 L`
`(1 xx22.4)/(27.3)=(32 xx 42)/(T_(2))`
`T_(2)= 1638 K`
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