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An ant starts from origin and moves to the mid- point of CD edge and stops there. It then moves to the mid-point of GF edge and again stops there. If P and Q are the midpoint fo CD and GF respectively, then find `bar(AB) + bar(PQ)`. The figure is a cube of side `1 m`.

A

`hat(i) + hat(j) + (hat(k))/(2)`

B

`hat(i) - hat(j) + (hat(k))/(2)`

C

`- hat(i) - hat(j) - (hat(k))/(2)`

D

`hat(i) + hat(j) - (hat(k))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`bar(AP) + bar(PQ) = bar(AQ)`
`A (0, 0, 0)`
`Q (1, 1, (1)/(2))`
So `bar(AQ) = hat(i) + hat(j) + (hat(k))/(2)`
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