If the unit of length be doubled in a new system of units then, numerical value of h (plank's constant) becomes `[E = hv]`

Options

A. Double
B. Half
C. `(1)/(4)` times
D. 4 times

Answer

C

Explanation

`[h] = M L^(2) T^(-1)`
`nu =` constant
`:.` Dimension of h for length is 2
`:.` When unit of length is double
unit of h become four times
hence its numeric part becomes `(1)/(4)` time.